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600x-2x^2=(x)
We move all terms to the left:
600x-2x^2-((x))=0
determiningTheFunctionDomain -2x^2+600x-x=0
We add all the numbers together, and all the variables
-2x^2+599x=0
a = -2; b = 599; c = 0;
Δ = b2-4ac
Δ = 5992-4·(-2)·0
Δ = 358801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{358801}=599$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(599)-599}{2*-2}=\frac{-1198}{-4} =299+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(599)+599}{2*-2}=\frac{0}{-4} =0 $
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